On the chance of dying in a game of Russian roulette

In a standard game of Russian roulette one bullet is inserted into an otherwise empty “six-shooter” revolver and the cylinder is then spun. Each player then takes turns putting the gun to their head and pulling the trigger until one of them dies.

So if you are forced to play a game of Russian roulette, is there any advantage to going first? Or to going last? Or is it best to play somewhere in the middle?

You might think that as the game progresses your chance of dying increases. In the first round there is a 1 in 6 chance of the bullet being lined up with the barrel; in the second round the chance rises to 1 in 5, all the way through to the final sixth round where the chance is 1 in 1, or certain.

But this is not correct, as you haven’t taken into account the chance that you won’t have to play because someone has already shot themselves in the face. If you multiply the chance of a bullet being in the chamber with the chance of having to play you can calculate the risk of dying in each round.

  • 1st round: 1/6 chance of dying × 6/6 chance of having to play = 1 in 6
  • 2nd round: 1/5 chance of dying × 5/6 chance of having to play = 1 in 6
  • 3rd round: 1/4 chance of dying × 4/6 chance of having to play = 1 in 6
  • 4th round: 1/3 chance of dying × 3/6 chance of having to play = 1 in 6
  • 5th round: 1/2 chance of dying × 2/6 chance of having to play = 1 in 6
  • 6th round: 1/1 chance of dying × 1/6 chance of having to play = 1 in 6

So the answer is no, the turn you take in a game of Russian roulette does not make a difference. Suffice it to say that playing a game of Russian roulette in any way is a Really Bad Idea.

One thought on “On the chance of dying in a game of Russian roulette

  1. Since you spin the cylinder every time before you pull the trigger, the change is always the same. 1 in 6. Even if you’re playing solitaire.

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